a rectangular octagonal pyramid has a base with edges of length 6ft and lateral surfaces with slant ht of 8 ft

what is the surface areas if the base area is b
what is the perimeter of the base

Answer by ironduke8159
If you mean a regular octagonal pyramid then the perimeter of the base is simply (8)(6)=48 feet.

The area of one of the unencumbered surfaces is (1/2)(6)(8) = 24 sq feet.
Since there are 8 such surfaces, the total area of the unencumbered faces is (24)(8)= 192 sq feet. Therefore the total surface area is 192+b.

I do not know of such a thing as arectangular octagonal pyramid.

What do you reckon? Answer below!

Answer by PoppaJ
V=b²h/3

Answer by rm
volume pyramid=basearea x height x 1/3

area = base ^2 = 11.439^2= 130.851 units^2

volume = 130.85 units^2 x 16.664 x 1/3 =
726.832 units^3

Answer by bigivima
v = lwh/3
v = (11.439*11.439*16.664)/3
v = 726.832 (cubic units)

Answer by CommanderJim
Go here

grapevine.abe.msstate.edu/~fto/tools/vol/index.htm

This site tells in detail how to obtain the volume of any geometric shape!!

Answer by Babu
ok, that’s certainly the formula.

now if u are attracted how we achieved that formula, u ‘ve to imagine a cuboid of base a sqaure of size ‘b’ and height h.

try to remove the pyramid from the cuboid.
u will find 4 half -pyramid left in the cuboid. These half-pyramids are equal in height.
so, there are over three pyramids in that cuboid.

volume of cuboid = b*b*h = volume of 3 pyramids.
volume of pyramid = 1/3 *Base* height

Though, the real formula comes from integrating the diffrerential volume.

What do you reckon? Answer below!

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